How to do Celestial Navigation in your Head
Introduction (last updated on December 11th 2016
These are the notes of a learning student and are meant to be taken as such. It is very possible that I am way
off in the methods that I will use below. Please consider this a theory.
It's my dream that someday I can look at the night sky and get a Roller Coaster Intuitive feel for where I'm at in the
Cosmos. The hardest part about understanding the heavens is that we are literaly inside the experiment, looking out,
trying to figure out our angle as part of the whole. In essance we are riding on the outside of a sphere that is revolving
around its own axis, and that is revolving around another solar body, the Sun. The fact that we can look out at other
solar bodies, and stars, and use them to determine where we are physically located on the ball has got to excite us.
What kind of man would we be if we never pondered our current physical location on the Earth in relationship to other
celestial bodies such as the Sun, Moon, Planets and Stars.
The ancient people would use the word 'Wanderers' in reference to the Sun, Moon, and Planets but to them they knew
that the positions of the stars never changed, that the stars were isotropic.
Knowing from our example below that we can estimate the longitude point on the Earth where Jupiter
intersects the Earth with a tangent line drawn from Jupiter to the Center of the Earth, we can go outside and
during some times of the right years, view Jupiter and imagine it passing through that point.
These are my notes on doing a Celestial Navigation 'Fix'. A Fix is a calculation that places you at a Latitude
and Longitude on the Earth that is calculated by viewing three celestial bodies above the Horizon. Once three
bodies are fixed, three circles are drawn on a globe of the earth and where these circles converge is where you
are at on the Earth. In these notes I will attempt to show how you can do this fix very roughly in your head
without an ephemeris, or nautical almanac. In this manner, we can better understand how it works when we use a
nautical almanac. We will only calculate one celestial body Jupiter since once we know how to do one, we can
You can read this and build some tools or you can just read this and imagine that you are using the
tools. The requirements for this project is as follows:
- World globe
- Time piece
- School protractor
- Soda straw
- Paper and pencil
- A bolt or nut to be used at the end of the string for a weight.
- Web access is optional
Pictures and tables
How to get the general idea of how to measure a celestial bodies distance from Zenith (directly over head)
Using a school protractor with a straw and string with a weight attached. We call this our own quadrant.
Remember that Jupiter is at a geocentric longitude of 191 degree's on our work date of April 26, 2005 Noon
Just for fun, if you where born on this day, the Astrologers would say that Jupiter was in Libra or opposite
Aries and note that Aries is 0 to 29 degree's longitude and Libra is 180 to 209 degree's longitude.
We will be using April 26, 2005 - 21:00 hours for our calculations so notice that in the Nautical Almanac below that 9:00 PM (21:00 Military time) in Salt Lake City Utah, USA is 3:00 Am the next day in Greenwich England where the Main time Meridian starts. We will use this table to see if the figures that we calculate match the ones shown here. See the red circled '21' and that we added 6 hours to that to get to the Greenwich time which is also circled.
This information came from this online nautical almanac site
Notice left column day 26 hour 21 the data: | 169 57.3 and that we are adding 6 hours to this to arive at last line
day 27 hour 3 | 260 12.1
View from a planetarium Program to find the 'First Point of Aries' or right ascension point 0
A picture of the sky from LAT 0, LON 84, (local) ST 0, facing North. As my friend recently showed me the picture
he says: "You can see the North Star just on the horizon, with the big dipper hanging down under the horizon
(the green line), as if you could see through the Earth. The celestial prime meridian can be drawn by extending a particular star in the big-dipper to Polaris (North star), and then a line from Polaris past Cassiopeia
and then continuing to your Zenith over-head and beyond to the Southern polar region on
the horizon". The big dipper is shown directly under the North star and is labeled 'Uma' for Ursa Major. Cassiopeia
is aligned directly above the North Star and is labeled 'Cas'. We will use this Celestial Prime Meridian in
our calculation so just remember that it runs through a star in Cassiopeia, the North Star, and then a star in
the Big Dipper. My friend calls this line the 24 hour clock hand. Note that the Cassiopeia side is the Prime Celestial Meridian (0-180 degrees) and the Big Dipper side is
the 180th meridian (180-360 degrees).
Below, the First Point of Aries is on top, and each Sector is 1 hour angle. Note that these Sectors widen out until they reach the Celestial Equator, and then they narrow until reaching the opposite pole (in this case the Southern Celestial pole). See this Wiki link for more discussion on hour angles by clicking here.
Image above is from ipoem.co.uk
Notice that the first point of Aries is at the top and that Cassiopeia occupies hour angles from 0 through 2.
Since Cassiopeia may look like an 'M' or a 'W' (W when on the bottom), you must remember a little rule to determine which side of the M or W is the 0 index also known as the 'first point of aries. The rule I use is:
"Cassiopeia is the Mother of the Heavens and everything starts with the first Star of her 'M' - for mother - and she created the heavens in just under 2 hours
(she occupies a little less than 2 hour angles)"
Note that now we can find the first point of Aries in the heavens, it is possible for instance to roughly estimate that Jupiter is at 191 degrees (not on this star map, see planet map above) opposite from it (on the Big Dipper side) of the imaginary line we can draw through Cassiopia, the North Star, and then the Big Dipper. Since we are doing celestial navigation in our head, you can see that it could be difficult to calculate a celestial bodies position this way however perhaps it could be done easier if we used a transparent piece of plexiglass with the center point being the north star.
Just in case you live to be thousands of years old, remember that With the 'Precession of the Equinox', measured in March each year, this map would rotate 360 degrees clockwise each 25,765 years (the cycle known as the 'Great Year'
Also notice that Cassiopeia spans the degrees from 0 to 30 and knowing that, you should be able to locate something if I told you it was at 191 degrees. Finding a point at 191 degrees is what this is all about, like reading longitude on a map of the Earth, simple once you break through and get it you are now beginning to see things in a beautiful new way, especially knowing that these degrees relate to time because in a two hour period, the Earth will rotate 30 degrees or put another way, the movement of the Earth will make the stars in the sky appear to be moving accross the sky 30 degress each and every two hours (double hour).
Real quick point is that if a pilot was flying due north at night, and say his destination was 3 degrees of latitude north, and it was a 12 hour flight, then the north star would slowly climb 3 degrees as he flew, and the celestial meridian line (24 hour clock hand) that we've been talking about would turn counter clockwise 180 degress, thereby guiding him on his flight.
Remember that star maps are two diminsional images of a three diminsional space, therefore imagine yourself inside a canalope that has been put back together but was sliced up into 12 even peices and halved perpendicular to the stem. The halved line is the celestial equator or the part of each piece where they are the widest. If you're viewing from a latitude of 45 North, then the halved line will be 45 degrees south of your zennith over-head. You could saw a hola-hoop in half, place one sawn end at due east and the other at due west, then tilt it to the south the same number of degrees that your latitude is (45), and that defines the celestial equator where each piece of the canalope is the widest. The view from inside this canalope is now very similar to what you could imagine the lat and long lines of the Earth would look like if you were in the center of the Earth. So now you know that the Celestial Spear has lat and long lines and that the Celestial Equator is the projection of the Earths equator into this celestial sphere. Also note that the Earths longitude lines go from 0 to 180 East and 0 to 180 West however the Celestial Sphere is 360 degrees. If you are looking South, the first point of aries would raise, then 2 hours later 30 degrees from the first point of aries, then 2 hours later 60 degress would raise, etc. So when looking North, the celestial bodies rotate counter clockwise around the north star, 30 degrees every 2 hours.
In Dutton's Nautical Navigation article, right ascention RA, is measured eastward from the first point of aries. When you think eastward in terms of the Celestial Sphere, imagine walking on top of it in an eastward direction similar to walking east on the sphere of the Earth.
Dutton's PDF Article
He goes on to say that most of the time, astronomers use Right Ascention (RA) which is measured eastward from the first point of aries but that (We) navigators use hour angle which is measured westward and expressed in units of arc rather than time as with RA. It gets confusing here but again navigators use hour angle measured in arcs even though they call those measurements hour angles. He further states that GHA refers to Greenwich hour angel, LHA means local hour angel, and SHA means sidereal hour angel.
So now using the solar system model above, move around counter clockwise from the first point of aries found at the top, to 191 degrees and you will see that Jupiter is there on our test date of April 26, 2005.
First do the calculations to get the latitude of the fix pin stick by the book, not in our head
According to the nautical almanac, Jupiters GHA on this date was 69. That means that our pin we use to do the fix will be stuck into the Earth globe somewhere on latidute 69.
So by looking at the nautical almanac above we can say that on April 26, 2005, the GHA of Aries was 260 and for Jupiter was 69. These
are the numbers that we will now try to calculate in our head. Write these down or remember them now and lets do
some math with them to get a feel of how this stuff works.
Now we will do the calculations to get the latitude using our head rather than using the almanac or ephemerus
First we need to calculating the GHA(Aries) in our head
The vernal equinox was on march 21, 2005 ( noon was 359.06.2 )
On April 26, at 21:00 hours:
Calculate GHA of aries as follows:
1 day for each day past vernal equinox = 36 days multiplied by ((360/365.25) gives an answer of int(35)
days. Remember this 35.
You can go to this site to see how the GHA of Aries on March 21 12 noon will be close to 0 degrees at the Nautical Almanac. This will be the case year after year if I'm doing this right.
You can click C L I C K H E R E T O S E E F O R Y O U R S E L F
Look for further emails on this natural medicine deal - it's fun, if nothing else. here now and paste this date into their date field and then click 'go get it'.
21:00 hours here in Salt Lake City is 03:00(Am) in Greenwich and 03:00 converted to degree's is 225
because noon is the 0 point when calculating GHA(Aries).
So 12:00 Midnight is 180 degree's plus 45 degree's for the 03:00 makes the 225.
225 + 35 = 260 and bingo, the nautical almanac above says GHA(Aries) for this date and time is in fact
260 (See Almanac above). Note that this is a measurement of how far the Earth has gone around the Sun since
the Vernal Equinox, and how the time of day tells us how much the Earth has spun around on this date.
Now we can estimate where Jupiter is so that we can make the calculation to find the fix longitude point
GHA=Greenwich Hour Angle
SHA=Sidereal Hour Angle, usually used to locate fixed stars on the celestial sphere. It uses the hour circle of the first point or Aries for it point of origin.
GP=geographical point where a celestial sphere intersects the Earth surface on a tangent to the center of the Earth
Sidereal=Relative to the stars
Wikipedia defines Right Ascension as follows: Right ascension (abbreviated RA; symbol a) is the angular distance measured eastward along the celestial equator from the vernal equinox to the hour circle of the point in question. When combined with declination, these astronomical coordinates specify the direction of a point on the celestial sphere in the equatorial coordinate system.
I think of RA as walking eastward around the Pole Star of the Celestial Globe the same way you would walk eastward around the North Pole of the Earth.
Looking at Jupiter in the night sky on this night and knowing where the first point of aries is, one could estimate that Jupiter is 191 degrees RA
from the first point of aries. Note that an ephemerus would also provide this same number. Also see the magenta colored illustration above.
Again, I will use April 26, 2005 at 21:00 hours SLC Utah (latitude 40 North Longitude 111 West) for
Again we know from the above almanac that on the test date, Jupiter's GHA is 69, and this is the number we want to arrive in our computation.
Since an our observation or an Ephemurus shows that Jupiter is at 191 degree's, we convert to RA by taking
the Complement of that to 360 and getting an SHA of 169.
GHA = SHA + GHA(aries)
GHA = SHA(Jupiter) + GHA(first point of aries) note: see nautical almanac above, or see how we will compute it shown below to get the GHA(aries))
Now we can calculate the GHA of Jupiter
So Jupiter GHA = (Jupiter's SHA) + (GHA (Aries))
x = 169 + 260
430 = 169 + 260
-360 (subtract 360 if answer is greater than 360)
And notice that the Almanac (see above) says Jupiter's GHA is 69
Note: not sure how to add in extra day since 21:00 plus 6 hours equals :03:00 next day.
So now we have the longitude and it's the same as Venezuela in South America. But we really need to use the celestial spheres
declination to gain the latitude before we can say that it's Venezuela.
The fact that we calculated the 69 is very significant because it is the same number that the nautical almanac shows. It is the
longitude point where we will stick the pin in the Earth's globe and will be somewhere around the same longitude as Venezuela South America, however, we now need to calculate the latitude for the pin to see if if will be in Venezuala or Brazil. Note that the middle of Venezuela is about latitude 7 north and longitude 67 East and it can be found at the northern most part of South America.
Now to get the latitude for the fix pin stick from the celestial sphere's declination (in this case Jupiter)
If we are using the nautical almanac to make the fix, we can simply do a lookup for Jupiter's Declination for that given day and hour. The declanation shown in the nautical chart above shows 2 hours 58 minutes south which we can round off to 3 degrees of latitude south of the equator. This will mean that the pin would be pegged at 3 degrees south latitude and 69 degrees west longitude, a place in Brazil south of Venezuela.
According to my studies, Jupiter's declination will head north for 6 years, then south for 6 years as it makes it's 12 year cycle around the Sun. In the year 2002 it made it's farthest journey north to about 23 degrees and then in 2008 it traveled 23 degrees south. So as I write this, Jupiter will be seen lower in the sky than I've seen it for 12 years.
If however, we are doing the fix in our head then we must continue by saying that declination is measured positive if a body is north of the celestial equatore and it is measured negitive if it is south of the celestial equator.
Since I live at latitude 40 North, the celestial equator is 40 degree's down from my zenith toward the
You could take a hula-hoop and saw it in half and hold one end at the east and the other at the west
(not magnetic). Now tilt it to the south so it aligns with your celestial equator. Now look through the
angle of the hula-hoop to Jupiter. See how many degree's it is North or South of the hula-hoop line
(Celestial equator) and this is the declination. You can also use the Quadrant that you made to make
this measurement. This declination of Jupiter is used to plot your latitude of the point where Jupiter
passes through the earth at this time. Remember that at the equator, the latitude is 0, and then moves
north or south 90 degree's. This same way, Jupiter may be north or south of the celestial equator, so simply
convert Jupiter's declination to latitude.
Now that the longitude and latitude are known, we can press a pin into the globe and it should be in northern Brazil
just south of Venezuela. If you don't have a globe, you won't be able to use the string but you can see the latitude
and longitude lines on the Earth at this Site
How to calculate the length of the string
Next we will calculate the length of a string that we will attached to the pin we stuck in Venezuela and use
it to draw a "circle of equal latitude" on the globe. Using the protractor (quadrant) we made above, we
measure the angle down from our zenith to Jupiter to get the zenith distance.
I think that my reading on April 26th was roughly 61 degree's. I used my self made quadrant. Now multiply
this 61 by the number 60 to get 3660. This is now the number of nautical miles that the length of the
string must be cut to. Knowing that a nautical mile is 1 minute, of a degree will also help. Cutting the
string to the length and attaching it to a pin, you should be able to draw one of the three arcs that are
needed to calculate where these three arcs converge thus giving you the fix or position where you are located on Earth.
If the the number of nautical miles is 3660 then divide that by 60 to get 61 and this is a rough approximation of the number of
degrees latitude that the string length must represent. The distance between degrees of longitude isn't constant because they
converge towards the poles.
Again, we now have the number 3660 which is the number of degrees that Jupiter is down from the Zennith (61) multiplied by 60 to equal 3660. Next
multiply this 3660 by 1852 which is the number of meters in a nautical mile to get 6,814,920. Now divide this 6,814,920 by meters per mile which
is 1609 to get the number (int)4236. Since the circumference of the Earth is about 24,000 miles, this 4200 is roughly 1/6th and 1/6th of 360 is
Note when you draw this circle on a flat map that the circle is distorted like a standing egg but it would be circular on a globe. See the
figure of the fix done on the wikipedia page link below. Also note that we want to see the arc drawn in such a place as to be close to
Salt Lake City, Utah which is located about 600 miles east of California in the United States.
Now we know where to place the pin in the globe and mark the geographical point or place where Jupiter is intersecting
the surface of the Earth as it transits to the center of the Earth.
I have often wondered when looking at the night sky how to calculate where the center of the Earth would
be and then knowing this in relation to where Jupiter passes for instance through Venezuela would be
remarkable. Could somehow knowing another Celestial body that passed through your location on its way to the
center of the Earth provide this viewing?
To Calculate where we are located
You need three celestial bodies to make this calculation and there are some real tricky aspects about using
the Sun and the Moon that you had better learn before using them. If you are lucky, you can use three
Since you placed a pin in the globe where Jupiter's intersected the Earth, and cut the string, (or used dividers)
at the calculated length, you know that you can draw an arc on the globe using that string.
You can do these same calculations with stars or other planets and by drawing 3 arcs, the place that they
intersect is where you are on the earth. You can use 2 celestial bodies instead of three if you have a
rough idea of where you are at. You can also use the Pythagorean theorem for other calculations.
Back to me trying to imagine my position in the cosmos, one way that I have used is to look at the full moon as it is raising
(a full moon rises as Sunset) and imagine that I am there at that given time standing on it. I imagine that it is the Earth that
I am standing on. This gets technical but I'm thinking that since I seem to be on the top of the Earth, that I would also be at
the top of the Moon and therefore the line between the would run perpendicular to my 0 declination or a 90 degree angle positive
declination (over my head and to the south). If I am correct, then this line on the Moon would then point to the North Star.
Please contact me on my contact page if you have any more insight to this.
References and Links:
Dutton's Nautical Navigation book
View Dividers tools used in place of string
Wikipdia on Celestial Navigation (see image of world map with two circles drawn for a fix)
Written by SDH